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2x^2+36x=-34
We move all terms to the left:
2x^2+36x-(-34)=0
We add all the numbers together, and all the variables
2x^2+36x+34=0
a = 2; b = 36; c = +34;
Δ = b2-4ac
Δ = 362-4·2·34
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-32}{2*2}=\frac{-68}{4} =-17 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+32}{2*2}=\frac{-4}{4} =-1 $
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